WebNov 17, 2016 · Find an answer to your question Calculate the pH of 0.005 M H2SO4. ritsmitasakans ritsmitasakans 17.11.2016 Chemistry Secondary School answered • expert … WebpH = 0.00 i.e [H+] = 1 (M) 250 ml of 1(M) H2SO4 solution = 250 ml of 2(N) H2SO4 solution. How , now I'm explaining the reason. Equivalent weight of H2SO4 = Mol. weight/ 2 = 49, so to convert the molarity to normality. We would multiply it by 2. Or you can evaluate the normality by this way Normality of H2SO4 = molarity × basicity (no of H+ ions)
Calculate the pH and the pOH of a 0.05M H2SO4 solution.
WebQ: Calculate the pH and pOH of: 0.3M sulfuric acid (H2SO4) solution A: Given: Molarity of H2SO4=0.3M Q: Calculate the pH for the following solutions: a. [H,Oʻ] = 1.4 × 10³M b. [OH'] 3.5 x 102M A: Click to see the answer question_answer question_answer question_answer question_answer question_answer question_answer question_answer question_answer WebCalculate the ph of 0.005M h2so4 solution ? Solution H2SO4 is a diprotic acid. The equation for its ionization is H2SO4 (aq) --> 2H+ + SO4- Equation tells us that each molecule of acid will produce 2 hydrogen ions, the concentration of the H+ ion must be 2 x (0.0050M) or .010M Using the definition of pH=-log [H+]= -log (.010M) = 2 Hence, pH is 2 chucky bathing suit
The pH of a solution of H2SO4 is 1 . Assuming complete ... - Toppr
WebAug 30, 2024 · What is the pOH when 5.0 L of a 0.45 M solution of sulfuric acid (H 2 SO 4) is titrated with 2.3 L of a 1.2 M lithium hydroxide (LiOH) solution? SOLUTION To solve this problem we must first determine the moles of H + ions produced by the strong acid and the moles of OH - ions produced by the strong base, respectively: Acid: WebMar 5, 2024 · And sulfuric acid is diprotic, and we could represent its reaction with water by the equation.... #H_2SO_4(l) + 2H_2O(l) rarr2H_3O^+ +SO_4^(2-)# And so #0.1*mol*L^-1# is #0.2*mol*L^-1# with respect to #H_3O^+#.. And thus #pH=-log_10(0.2)=-(-0.699)=0.699#.. And on the other hand, #0.1*N# sulfuric acid is in fact #0.05*mol*L^-1# with respect to … WebHow do you find the pH of 0.1 m H2SO4? pH= -log (H+) Here H+ refers to the concentration of H+ ions or the Hydronium ions. Here it can be clearly observed that 1 moles of sulphuric acid gives rise to 2 moles of H+ ions. which is equal to 1.698. Therefore pH of 0.01 moles of H2SO4 is 1.698 or 1.70. chucky bedding set